Question

How much does 9x sq+7x-2 exceeds to 4x sq. +3x+1
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Answer 1

Answer:

$9 {x}^{2} + 7x - 2 - (4 {x}^{2} + 3x + 1)$

$= 9 {x}^{2} + 7x - 2 - 4 {x}^{2} - 3x - 1$

$= 5 {x}^{2} + 4x - 3$

Answer 2

Answer:

Hope this will help you.

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