Question

How much does 9xsq.+7x-2 exceeds to 4xsq. + 3x+1​

Answer 1

Answer:

$9 {x}^{2} + 7x - 2 - (4 {x}^{2} + 3x + 1)$

$= 9 {x}^{2} + 7x - 2 - 4 {x}^{2} - 3x - 1$

$= 5 {x}^{2} + 4x - 3$