Question

*How much does it cost to paint a cuboidal wooden box of 2 m length, 1 m width and 1 m height at the rate of Rs 40 per sqm.?*

1️⃣ Rs 400
2️⃣ Rs 800
3️⃣ Rs 240
4️⃣ Rs 480​

Answer 1

Answer:

Given :-

• A cuboidal wooden box of 2 m length, 1 m width and 1 m height at the rate of Rs 40 per sq.m.

To Find :-

• How much does it cost to paint a cuboidal wooden box.

Formula Used :-

߷︎ Total surface area of Cuboid :

★ T.S.A of Cuboid = 2(lb + bh + hl) ★

where,

• l = Length
• b = Breadth
• h = Height

Solution :-

First, we have to find the total surface area of a wooden box :

Given :

• Length (l) = 2 m
• Breadth (b) = 1 m
• Height (h) = 1 m

According to the question by using the formula we get,

↦ T.S.A of Cuboid = 2(2 × 1 + 1 × 1 + 1 × 2)

↦ T.S.A of Cuboid = 2(2 + 1 + 2)

↦ T.S.A of Cuboid = 2(5)

↦ T.S.A of Cuboid = 2 × 5

➠ T.S.A of Cuboid = 10 m²

Hence, the total surface area of a wooden box is 10 m².

Now, we have to find how much does it cost to paint a cuboidal wooden box :

Given :

• T.S.A of Cuboid = 10 m²
• Rate = Rs 40 per sq.m.

Then,

⇒ Total cost = Rs 40 × 10

➦ Total cost = Rs 400

∴ The cost to paint a cuboidal wooden box is Rs 400 .

Hence, the correct options is option no 1) Rs 400 .

Answer 2

$\frak{Given}\begin{cases}\sf{Length=2\: m} \\ \sf{Width=1\: m}\\ \sf{height=1 \:m } \\ \sf{cost\:=Rs.40\:per\:m^2}\end{cases}$

To find:- cost of painting wooden box.

${\mathfrak {\underline{\dag {Let's \:do \:it\:!}}}}$

$\sf\star{\boxed{\pink{TSA \:of \:wooden\: box=2(l×b+b×h+l×h)}}}$

• where l is length of box b is the breadth that is width of box and h is the height of box.

$\sf \implies {2(2×1+1×1+2×1) m^2} \\ \sf \implies {2(2+1+2)m^2} \\ \sf \implies{2(5)m^2} \\ \sf \implies {\boxed {\pink{10\:m^2}}}$

cost per $\sf m^2$=Rs.40

cost for $\sf 10 \:m^2$=Rs.40×10=Rs.400

$\odot$Rs 400

O Rs 800

O Rs 240

O Rs 480