how much does x^2 - 2ax +5 exeed 3x^2 - 5x+6
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Answer:
2x^2 + (2a-5)x + 1
Step-by-step explanation:
Subtracting x^2 - 2ax +5 from 3x^2 - 5x+6, we get
(3x^2 - 5x+6) - (x^2 - 2ax +5)=2x^2 + 2ax-5x + 1
=2x^2 + (2a-5)x + 1
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