Math, asked by nishantbana13, 7 months ago

How much does x²– xy +. 4b² exceed–2x²–7xy+5b²?

Answers

Answered by 2019swetaraj

21

Answer:

x²– xy +. 4b² -(–2x²–7xy+5b²)

=x²– xy +. 4b²+2x²+7xy-5b²

=3x²+6xy-b²

Answered by manoj06031973

1

Answer:

x²-xy+4b-(-2x²-7xy+5b²)

=x²-xu+4b²+2x²+7xy-5b2

=3x²+6xy-b²ÁÑS

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