Question

how much dyne is in one newton ?(by dimensional method) answer in 80 to 100 words
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Answer 1

Answer:

$1N=10^5Dyne$

Explanation:

we know that

F = m × a

1N = Kg × $m/sec^2$

$1N =\frac{10^3gram*10^2cm}{sec^2}$

$1N=10^5gram*cm/sec^2$

$1N = 10^5Dyne$

hence,

           it is proved that 1N=10^5Dyne