Physics, asked by sapnasofty879, 11 months ago

How much e.m.f. will be induced in a 10H inductor in which the current changes from 10A to 7A in 9 × 10–2s?

Answers

Answered by JaiManani
0

Answer:

3.33*10^2 approximately is right Ans

Answered by gadakhsanket
8

Dear Student,

◆ Answer -

E = 333.3 V

● Explaination -

# Given -

L = 10 H

I1 = 10 A

I2 = 7 A

dt = 0.09 s

# Solution -

EMF induced is calculated by formula -

E = -L.di/dt

E = -L × (I2-I1) / dt

E = -10 × (7-10) / 0.09

E = 333.3 V

Therefore, EMF induced in the inductor is 333.3 V.

Thanks dear. Hope this helps you...

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