How much e.m.f. will be induced in a 10H inductor in which the current changes from 10A to 7A in 9 × 10–2s?
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Answered by
0
Answer:
3.33*10^2 approximately is right Ans
Answered by
8
Dear Student,
◆ Answer -
E = 333.3 V
● Explaination -
# Given -
L = 10 H
I1 = 10 A
I2 = 7 A
dt = 0.09 s
# Solution -
EMF induced is calculated by formula -
E = -L.di/dt
E = -L × (I2-I1) / dt
E = -10 × (7-10) / 0.09
E = 333.3 V
Therefore, EMF induced in the inductor is 333.3 V.
Thanks dear. Hope this helps you...
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