How much electric charge is required to oxidise 1 mole of h2o to o2?
Answers
Answered by
5
Consider the equation
2H2O ---> O2 + 4H+ + 4e-
During the liberation of 1 mole of oxygen 4 electrons are involved.
1 faraday = 6.023x10^23 electrons
No.of Faraday = No. of electrons passed through/ 6.023x10^23
= 4/6.023x10^23
= 0.664x10^-23 F
2H2O ---> O2 + 4H+ + 4e-
During the liberation of 1 mole of oxygen 4 electrons are involved.
1 faraday = 6.023x10^23 electrons
No.of Faraday = No. of electrons passed through/ 6.023x10^23
= 4/6.023x10^23
= 0.664x10^-23 F
Similar questions
English,
7 months ago
Psychology,
7 months ago
Chemistry,
1 year ago
Biology,
1 year ago
English,
1 year ago