Question

How much electric flux will come out through a surface a S= 10j kept in an electric field E=2i+4j+3k

Answer 1

Answer:

Explanation:

Here is the answer that you're looking for

Answer 2

Note: The correct question must be provided with following options-

How much electric flux will come out through a surface $S=10\hat{j}$ kept in an electrostatic field $\vec{E}=2\hat{i}+4\hat{j}+3\hat{k}$ ?

a) $20 units$

b) $40 units$

c) $70 units$

d) nearly $80 units$

Explanation for correct option

b:

Electric flux is the measure of the electric field through a given surface in electromagnetism.

We know that,

$\phi_{E} =\vec{E}.\vec{S}$

where, $\phi_{E}$ is the electric flux, $E$ is the electric field and $S$ is the area of the surface.

$\phi_{E} =(2\hat{i}+4\hat{j}+3\hat{k}).(10\hat{j})=40 units$

Thus, the electric flux  of $40 units$ will come out through a surface  $S=10\hat{j}$ kept in an electrostatic field $\vec{E}=2\hat{i}+4\hat{j}+3\hat{k}$.

Explanation for incorrect options

a,c,d:

The electric flux does not to evaluate to either $20 units$, $70 units$

or nearly $80 units$.

Thus, options a, c and d are incorrect.

Hence, option b) is correct.

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