How much electricity in terms of Faraday is required to produce (i) 20.0 g of Ca from molten CaCl2.
Answers
Answered by
5
According to the question,
Ca^2+ +2e^- -----------------> Ca(40g)
Electricity required to produce 40 g of calcium = 2 F
Therefore, electricity required to produce 20 g of calcium = (2x20) / 40
= 1 F
Ca^2+ +2e^- -----------------> Ca(40g)
Electricity required to produce 40 g of calcium = 2 F
Therefore, electricity required to produce 20 g of calcium = (2x20) / 40
= 1 F
Answered by
0
Explanation:
Acc. to question ,
the reduction reaction will be
(Ca²+) + (2e-) -----------> (Ca)
( atomic weight = 40g )
electricity required to produce 40g of calcium = 2F
Therefore,
electricity required to produce 20g of calcium = ( 2 × 20 )/40 = 40/40 = 1F
Similar questions