How much electricity in terms of faraday is required to produce 2 moles of aluminium metal from molten alumina?
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The balance reaction will
The charge on Ca in CaCl2
Ca + 2Cl ���� = 0
Cl has �1 charge so that
Ca� + 2(�1) = 0
Ca� ������������ = 2
We have to get 2o g Ca from Ca2+
Number of required moles� = mass / molar mass
Molar mass of Ca is 40 g/mol and required mass of Ca is 20 g
Hence number of moles� �������� = 20/40 ���� = 0.5 mol
Electricity required to produce 1 mol of calcium = 2 F
The electricity required to produce 0.5 mol of calcium
= 0.5 � 2 F
�� = 1 F
(ii)
Charge on Al in Al2O3
2Al� + 3O = 0
Oxygen has �2
2Al +3(�2) � = 0
Al ������� = 3
Change transfer� n = 3
Charge required for 1 mol of Al ���= 3F
Number of moles of Al� = 40 /27� = 1.48
The electricity required to produce 1.48 mol of Al = 1.48� � 3 F
= 4.44 F
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