How much electricity is required in coulomb for oxidation of 1 mol of H20 to O2
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2 Faraday........as in H20 the oxidation state of oxygen is -2 n when it gets oxidizes to O2 it's oxidation state is 0 so total change in oxidation state in this reaction is (2-0) = 2 so 2 Faraday's of electricity is required i.e 2×96500=193000 (1Faraday=96500)
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Hey !!
→ 1 mol of H₂O to O₂
The electrode reaction for 1 mol of H₂O is given as,
H₂O ------> 2H⁺ + 1/2 O₂ + 2e⁻
∴ Quantity of electricity passed required = 2F
= 2 × 96500 c
= 193000 C
Hope it helps you !!
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