Question

how much electricity is requred to prepare 5.12 kg al. by electrolysis
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Answer 1

Step-by-step explanation:

Mass = 27 amu; 1 Faraday = 96,500 Coulombs). The cathode reaction is. To prepare 5.12 kg of aluminium metal by this method we require (a) 5.49 × 10¹ C of electricity(b) 5.49 × 10⁴ C of electricity(c) 1.83 × 10⁷ C of electricity(d) 5.49 × 10⁷ C of electricity.

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Answer 2

Answer:

5.490 × 10⁷C

Step-by-step explanation:

Considering aluminium is prepared from alumina

Al2O3 -> Al

Equivalents of Al produced = 5.12x10³/9 = 5120/9 Equivalent Mass of At = 27/3 = 9 g/equivalent)

:. Amount of charge passed. 5120/9 F

:. Amount of charge passed in Coulomb = 5120/9 96500

= 5.490×10⁷ C