Question

How much energy associated with radiation of wavelength 200nm?

Answer 1

Explanation:

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Answer 2

Explanation:

Given

Lemda = 200nm

E = hC/lemda

So

h = 6.6*10^-34

c = 3*10^8m/s

So

E =6.6*10^-34*3*10^8/2*10^-7 m

E = 9.9*10^-19