how much energy consumee is when current 5ampere? flow through an filament of a metre having a resistance 100 ohm! for 2 hrs?
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Answered by
5
energy consumed = I^2RT
E= 5*5*100*2
E=5000J
E= 5*5*100*2
E=5000J
Crytek1512:
Same Tou You Bro
Answered by
0
We know that,
Power (P) = I²R
Here, I = 5 A, R = 100 Ohms
Therefore, Power = 25*100 = 2500 W
Energy Consumed = Power*Time
= 2500*2 = 5000 J
Hope it Helps!
Power (P) = I²R
Here, I = 5 A, R = 100 Ohms
Therefore, Power = 25*100 = 2500 W
Energy Consumed = Power*Time
= 2500*2 = 5000 J
Hope it Helps!
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