Question

How much energy is converted by a device that draws 0.5A from a 12V battery for 2 hours ​

Answer 1

Answer:

Amount of charge = 1 coulomb or 1C

          Potential difference = 6V

          Energy or work done = ?

          Work done or energy = V × Q[Q is the amount of charge flowing between two points at potential difference V = 6]

          i.e., W = V × Q

                  W = 6 × 1

          Work done or energy = 6 joules.

Explanation:

Answer 2

r

1

=2 ohm,r

2

=2 ohm

E

1

=12V,E

2

=18V

E

net

=E

2

−E

1

=18−12=6V

r

net

=r

1

+r

2

=4 ohm

i=

r

net

E

net

=1.5A

V

T

1

=18−(1.5)(2)=15V

V

T

2

=12+(1.5)(2)=15V

Power =

R

V

2