How much energy is converted by a device that draws 0.5A from a 12V battery for 2 hours
Answers
Answered by
17
Answer:
Amount of charge = 1 coulomb or 1C
Potential difference = 6V
Energy or work done = ?
Work done or energy = V × Q[Q is the amount of charge flowing between two points at potential difference V = 6]
i.e., W = V × Q
W = 6 × 1
Work done or energy = 6 joules.
Explanation:
Answered by
0
r
1
=2 ohm,r
2
=2 ohm
E
1
=12V,E
2
=18V
E
net
=E
2
−E
1
=18−12=6V
r
net
=r
1
+r
2
=4 ohm
i=
r
net
E
net
=1.5A
V
T
1
=18−(1.5)(2)=15V
V
T
2
=12+(1.5)(2)=15V
Power =
R
V
2
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