How much energy is dissipated in 10 min when a current of 4.0A is flowing through a potential drop of 60v
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Answered by
8
using V=IR,
60=4R
15=R
using energy=I*I*R*T,
E=4*4*15*10*60
E=144000
60=4R
15=R
using energy=I*I*R*T,
E=4*4*15*10*60
E=144000
Answered by
6
E=VIt=60×4×600=144 kJ
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