How much energy is in the elastic potential energy store of a spring with a spring constant of 4 N/m if it is stretched from 1 m to 1.1 m in length?
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Answer:
0.02joules
Explanation:
elastic pe=1/2*k*(delta x) ^2
=1/2*4*(1.1-1)^2
=1/2*4*0.1*0.1
=0.02J
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