Question

How much energy is in the elastic potential energy store of a spring with a spring constant of 4 N/m if it is stretched from 1 m to 1.1 m in length?

Answer 1

Explanation:

Spring force constant (k)

N/m

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Spring stretch length (Δx)

m

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Spring potential energy (U)

Answer 2

Answer: 0.02 J

Explanation:

elastic potential energy = 1/2 × spring constant × (extension) squared

First calculate the extension of the spring:  

extension = final length – length at rest = 1.1 m – 1 m = 0.1m

Substitute values into the equation:

elastic potential energy = 1/2 × 4 N/m × (0.1 m) squared

elastic potential energy = 0.02 J