Question

How much energy is involved in the combustion of 1.8 g of glucose

Answer 1

Answer:

How much heat energy if evolved in the combustion of 1.8g of glucose? 15.2 kJ.

Answer 2

Answer:

29$kJ$ energy is involved in the combustion of 1.8 g of glucose.

Explanation:

To find the energy involved in a chemical reaction we need to find the energy that has been released during conducting the reaction and the energy that has been absorbed to carry out the reaction. Subtracting the energy absorbed from the energy released gives us the net energy involved in the reaction. Here we have to find out the energy involved in the combustion of glucose. The chemical equation for the combustion of glucose is:

$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \rightarrow 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) ; \Delta H=-2900 k J$

The above equation is the combustion of one mole of glucose: that is 180g glucose.

on combustion of 180g glucose energy involved = 2900$kJ$

on combustion of 1g glucose energy involved = $\frac{2900}{180}$= 16.11$kJ$

∴ on combustion of 1.8g glucose energy involved = 16.11×1.8 = 28.99$kJ$

                                                                                                    ≈ 29$kJ$