Question

How much energy is released in the following reaction?

1H2 + 1H2 = 2He4 

If the B.E./Nucleon of 1H2 and 2He4 are 1.123 MeV and 7.2 MeV respectively.​

Answer 1

Answer:

B. E. of 1 H₂

ΔE = 1.125

E = A × ΔE

E = 2 × 1.125

= 2.25 MeV

B.E. of two 1H₂ = 2.25

Ed = 4.5 MeV

B.E. of an α -particle = 4 × 7.2

Ea = 28.8

Energy released ER = Ea – Ed  

Energy Released = 28.8 – 4.5

= 24.3 MeV

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Answer 2

Answer:

Answer Verified. Force is a push or a pull that changes or tends to change the state of rest or uniform motion of an object or changes the direction or shape of an object. It causes objects to accelerate. SI unit is Newton.