how much energy is released or absorbed when 1 gm of steam at 100 C turns to ice at 0 C
Answers
Answered by
104
Heat released during phase transitions,
steam → water 540 cal & water → ice 80 cal
Heat released during fall in temperature of water (100°→0°) is 1(100)=100 cal
Total heat released is 540+100+80=720 cal
steam → water 540 cal & water → ice 80 cal
Heat released during fall in temperature of water (100°→0°) is 1(100)=100 cal
Total heat released is 540+100+80=720 cal
Answered by
16
Q = 540 + 100 + 80
= 720 calories
mark it as a brainlist answer
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