Question

How much energy is released or absorbed when 1gm of steam at 100 degree Celsius turns to ice at 0 degree celsius​

Answer 1

Explanation:

${ \huge \fbox \pink {A}\fbox \blue {n} \fbox \purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}}$

Here m = 1 gm; S = 1 Cal/gm°CΔT = 100°C – 0°C ⇒ 100°C = 1.1. 100 = 100 CalStage – 3 : Heat energy releases from water 0°CWhen converts into ice 0°CQ3 = Latent heat of fusion Lfusion = 80 Cal.

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Total energy releases = Q1 + Q2 + Q3 = 540 + 100 + 80 = 720 Cal.

@MrInevitable☃️