Question

How much energy is released when 1 gram of mass is lost during the nuclear reaction? in Mev

Answer 1

According to the famous equation of mass-energy conversion:

E=mC^2

Where,

E= energy released or absorbed during reaction

m= mass of particle

C= speed of light or photons= 3*10^8 m/sec

So, using this formulae,

Energy released= [{1*10^(-3)} * (3* 10^8)^2] joules = 9*10^13 joules = 90 TJ.

Basically this energy-mass conversion equation is used in such kind of calculations throughout.

Hope this might answer your doubts.

Thanks and regards.

Answer 2

heya


You mean during the nuclear fission reaction,each atom produces a bout 200 MeV,
according to Avogadro each 1 mole-gm contains about 10^23 atoms(check it).So Igm
releases about 2X10^25 MeV.

According to the famous equation of mass-energy conversion:

E=mC^2

Where,

E= energy released or absorbed during reaction

m= mass of particle

C= speed of light or photons= 3*10^8 m/sec

So, using this formulae,

Energy released= [{1*10^(-3)} * (3* 10^8)^2] joules = 9*10^13 joules = 90 TJ.

Basically this energy-mass conversion equation is used in such kind of calculations throughout.

Hope this might answer your doubts.