How much energy is released when 1gm of water at 0^oC freezes to ice at 0^oC
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To calculate the amount of heat entering or leaving a system, the equation Q=mcΔT is used.
Explanation:m = mass (in grams)
c = specific heat capacity (J/g°C)
ΔT = change in temperature (°C)
Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.
The mass given is 25.0 grams.
As for the change in temperature, I will assume that it start off at room temperature, 25°C.
25°C−0°C=25°C
Q=mcΔT
Q=25grams⋅4.19Jg°C⋅25°CQ
=2618.75JSimilar questions