How much energy is required to ionise a H atom if the electron occupies n = 5 orbit? Compare your answer with the ionization enthalpy of H atom ( energy required to remove the electron from n =1 orbit)
NCERT Class XII
Chemistry - Main Course Book I
Chapter 2. Structure of Atom
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n = 5 shell O in the atom.
Ionization energy enthalpy of Hydrogen atom Z = 1, n = 1, to remove electron from 1S orbital... = 13.6 eV
Ionization energy = E =
The ionization energy is inversely proportional to the square of n... so it is 1/25 th or 4% of the ionization energy of Hydrogen atom for the electron in K orbit.
Ionization energy enthalpy of Hydrogen atom Z = 1, n = 1, to remove electron from 1S orbital... = 13.6 eV
Ionization energy = E =
The ionization energy is inversely proportional to the square of n... so it is 1/25 th or 4% of the ionization energy of Hydrogen atom for the electron in K orbit.
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