how much energy is required to ionize H atom if the electronic occupies 5th shell. compare the answer with ionization energy of H atom
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Explanation:
The energy of an electron in nth orbit is E=
n
2
−21.8×10
−19
J/atom.
The ionization energy for the electron in the fifth orbit is:
ΔE=E
2
−E
1
=−21.8×10
−19
n
2
2
1
=
n
1
2
1
ΔE=E
2
−E
1
=−21.8×10
−19
∞
1
=
5
2
1
=8.72×10
−20
J.
The ionization energy for the electron in the first orbit is:
ΔE
′
=E
2
−E
1
=−21.8×10
−19
n
2
2
1
=
n
1
2
1
ΔE
′
=E
2
−E
1
=−21.8×10
−19
∞
1
=
1
2
1
=21.8×10
−19
.
The ratio of the ionization energy of electron in first orbit to the ionization energy of electron in fifth orbit is:
ΔE
ΔE
′
=
8.72×10
−20
21.8×10
−19
=25.
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