how much energy is required to raise the tempertaure pf 20 kg of water from 0 degrees celcius to 35 degrees celcius?
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E=mS∆T
S for water=4.1
E=20kg*4.1*(35-0)=20*1000g*4.1*35
=2,870000J=2,870kJ
was it helpful??
S for water=4.1
E=20kg*4.1*(35-0)=20*1000g*4.1*35
=2,870000J=2,870kJ
was it helpful??
tharealprettygirl:
it was incorrect, but thanks for the help.
how it is incorrect?
specific heat is 4.186JKg/C , mass is 20Kg , the change in temperature was 35 degrees celcius beacuse 35c - 0c is 35 you muliply them and you recieve the anwser of 293.02KJ
i just used S=4.1 for easy calculation....and accordingly its correct
definitely wrong! during an assignment in class you will need to round or use the exact caculation.
the way you did it , i understand where you were coming from, but also it isn't exactly the best way to do it, you should never try and summarize a calculation or try and take the short way out because, its a HUGE possibility that you'll get the answer wrong.
you should be thankful that i helped you and stop arguing...it was just a demo to show the procedure to you so that you can do it by yourself
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