how much energy is required to remove an electron from the n=8 state of a hydrogen atom ?
Answers
Answered by
0
Answer:
Given: n=2
For hydrogen atom the ground state energy is E
0
=−13.6eV and Z = 1. The energy of electron in n
th
state is
E
n
=
n
2
E
0
×Z
2
E
2
=
(2)
2
−13.6×(1)
2
E
2
=−3.4eV
Hence, the energy required to remove an electron from $$n=2$$ state in hydrogen is +3.4 eV.
Answered by
1
Correct option is
B
3.4eV
Given: n=2
For hydrogen atom the ground state energy is E
0
=−13.6eV and Z = 1. The energy of electron in n
th
state is
E
n
=
n
2
E
0
×Z
2
E
2
=
(2)
2
−13.6×(1)
2
E
2
=−3.4eV
Hence, the energy required to remove an electron from $$n=2$$ state in hydrogen is +3.4 eV.
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