how much energy is transferred from one gram of boiling water at hundred degree Celsius cools to water at zero degree celsius
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Answer:
Mass of water (m) = 1g
initial temperature (T1) = 0 c
Final temperature (T2) = 100 c
specific heat of water (s) = 1cal / g-c
heat energy transferred Q = ms (T2-T1)
Q = 1x1x(100-0)
= 100 cal
100 cal is the temperature
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