Question

How much energy is transferred when 12gm of boiling water at 100°C cools to
water at 0°C?​

Answer 1

Answer:

Q = mL = 1 × 80 = 80 cal. Water at 100°C → Water at 0°C Q2 = 100 cal from point bWater at 0°C → Ice at 0°C Q3 = 80 cal from point c∴ Total energy released Q = Q1 + Q2 + Q3 = 540 + 100 + 80 = 720 cal.