Question

How much energy is trsnferref when 1 gm of boiling water 100 c cools to water at 0 c

Answer 1

Explanation:

Q=m×Lv , where Lv is the latent heat of vaporisation. So the energy needed for 1 gram of water is 540 cal. This is the heat needed for the conversion of boiling water at 100 ∘C to water at 100 ∘C. To change the water to 0 ∘C the transfer of energy will be an additional 100 cal.

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