Question

how much energy will be required to heat 1 gm of water from 30 deg c to 40 deg c

Answer 1

q=msdeltat
s for water is =4.18 J/gm -c
=1x4.18x10
=41.8J

Answer 2

$\Delta Q=m\ s\ \Delta T=1 gm*4.1813\ Joules/gm/degC*(40-30) degC\\\\.\ \ \ =41.813\ Joules.$

Specific heat capacity s of water at constant pressure or isobaric = 4.1813 J/gm/degC