Question

how much energy will be stored by a capacitor of 470 microfarad charged by a battery of 20 v? ​

Answer 1

Answer:

E=1/2CV2

1/2*470*10^-6*400=.094 JOULES

Answer 2

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

Energy stored in capacitor ,

E = ½ CV²

E = ½ x 470 x 10^-6 x 20 x 20

E = 47 x 2 x 10^-3

E = 94 x 10^-3 J

$\mathscr{\large{Hope\:helps\:}}!! \\ \\ {GRACIAS!!}$

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