how much enery is relased or observed when 1gm of ice at 0 cel turl into 1 gm of vapour at 100 cel
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A large amount of energy will be absorbed because to convert ice to water and water to vapour, we need to heat it.
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1 gm of ice at 0 ⁰C to turn into 1 gm of vapour at 100 ⁰C
1) 1 gm of ice takes the latent heat of fusion to melt into water.
heat energy needed = 1 gm * 334 Joules/gm = 334 J
2) 1 gm of water heats up to 100°C as water
heat energy needed = mass * specific heat * temperature difference
= 1 gm * 4.18 J/gm/°C * 100°C = 418 Joules
3) 1 gm of water at 100°C changes physical state into vapour
heat energy needed = latent heat of vaporization
= 1 gm * 2260 J/gm = 2260 J
total energy absorbed by the water = 334 + 418 + 2260 = 3, 012 Joules
1) 1 gm of ice takes the latent heat of fusion to melt into water.
heat energy needed = 1 gm * 334 Joules/gm = 334 J
2) 1 gm of water heats up to 100°C as water
heat energy needed = mass * specific heat * temperature difference
= 1 gm * 4.18 J/gm/°C * 100°C = 418 Joules
3) 1 gm of water at 100°C changes physical state into vapour
heat energy needed = latent heat of vaporization
= 1 gm * 2260 J/gm = 2260 J
total energy absorbed by the water = 334 + 418 + 2260 = 3, 012 Joules
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