Question

how much fencing will be required to fence a squre field of area 10 m squre 24 dm squre​

Answer 1

Answer:

Step-by-step explanation:

total area = 118sq.m + 81 sq.dm

1m= 100 cm so 118 sq.m = 118× 10000 sq.cm = 1180000 sq.cm

1dm = 10cm so 81 sq.dm = 81× 100 sq.cm = 8100 sq.cm

total area is 1180000 + 8100 sq.cm = 1188100sq.cm

so as we have the area of square field from that we can find side of square field

so each side of square field is 1090cm

since 1090squared = 1188100 which is area

so side of square is 1090cm= 109m

so the fencing required is equal to perimeter which is 4 × side

so length of fencing required is 4×109 = 436m