How much fencing would be required to fence a square field with an area of 118 sq.metres and 81 sq.decimeters?
Answers
Answered by
9
total area = 118sq.m + 81 sq.dm
1m= 100 cm so 118 sq.m = 118× 10000 sq.cm = 1180000 sq.cm
1dm = 10cm so 81 sq.dm = 81× 100 sq.cm = 8100 sq.cm
total area is 1180000 + 8100 sq.cm = 1188100sq.cm
so as we have the area of square field from that we can find side of square field
so each side of square field is 1090cm
since 1090squared = 1188100 which is area
so side of square is 1090cm= 109m
so the fencing required is equal to perimeter which is 4 × side
so length of fencing required is 4×109 = 436m
1m= 100 cm so 118 sq.m = 118× 10000 sq.cm = 1180000 sq.cm
1dm = 10cm so 81 sq.dm = 81× 100 sq.cm = 8100 sq.cm
total area is 1180000 + 8100 sq.cm = 1188100sq.cm
so as we have the area of square field from that we can find side of square field
so each side of square field is 1090cm
since 1090squared = 1188100 which is area
so side of square is 1090cm= 109m
so the fencing required is equal to perimeter which is 4 × side
so length of fencing required is 4×109 = 436m
Similar questions