Question

How much FeS(Fe = 56 , S = 32) will be required to react with dilute H2SO4 for producing 2.24L gas at STP ? Please tell...​

Answer 1

Answer:

FeS+H2SO4=FeSO4+H2S

1mole+1mole= 1mole+ 1mole

see..same moles of each requires to produce H2S gas

one more note: it is said that 2.24L gas i.e, H2S

1mole of any gas at stp occupies 22.4 liters of volume .

so 22.4 lit for 1mole

thus 2.24 lit for 0.1 mole

this simply means that for producing 0.1 mole of gas it requires 0.1 moles of FeS

moles=weight/ molecular wght

0.1=weight/56+32

0.1=weight/88

weight=0.1×88= 8.8

...so 8.8 gm of FeS is required to produce 2.24 litre of gas

Answer 2

Didu no need to thank his answers please

he is a cheater just take thanks from others but never gave back today I am working from this phone so when I see your answer then I thank your answers else he will never thank your answers