Question

How much force (in N) is exerted on one side of an 14.8 cm by 21.0 cm sheet of paper by the atmosphere?

Answer 1

The force exerted by the atmospheric pressure on the paper is 3139 N.

We know that the atmospheric pressure is 1.01×$10^{5}$ N/m^2

Area of the paper is =14.8*21=310.8 cm^2=0.03108 m^2

Now the pressure is defined as force per unit area

Pressure=Force/Area

Plugging the values in the above equation

1.01×$10^{5}$=F/0.03108

F=3139 N

Therefore, The force exerted by the atmospheric pressure on the paper is 3139 N.