Question

How much force is exerted on a 13kg object accelerating from 20m/s to 12m/s in 3.5s?

A. 29.7N B. 297N C. 2.97N D. -29.7N​

Answer 1

Answer:

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Answer 2

Given:

• Mass of the object = 13 kg

• Initial velocity = 20 m/s

• Final velocity = 12 m/s

• Time taken = 3.5 s

To find :-

• Force

Solution :-

We first need to find the acceleration in order to do that simply use the first equation of motion

⟹ v = u + at

here ,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time taken

⟹ 12 = 20 + a x 3.5

⟹ 3.5 a = -8

⟹ a = -8 /3.5

⟹ a = - 2.28 m/s²

Note : negative sign denotes deceleration

Now that we have the acceleration of the object let's find it's force

By using Newton's Second Law of motion ,

⟹ F = ma

⟹ F = 13 x -2.28

⟹ F = - 29.64 N

⟹ | F| = 29.64 N

The magnitude of force acting on the object is 29. 64 N