how much force is exerted on a 3 kg object accelerates from 12 m/s to rest in 5.5 seconds
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Let 'f' be the required force .
We know that,
f = ma = m(v-u)/t. ,where t = time,u= initial velocity , v = final velocity ,and m= mass
= 3(0-12)/5.5
= 0- 36/5.5
= -360/55
= -6.54 N (approx)
We know that,
f = ma = m(v-u)/t. ,where t = time,u= initial velocity , v = final velocity ,and m= mass
= 3(0-12)/5.5
= 0- 36/5.5
= -360/55
= -6.54 N (approx)
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