Question

How much force is required to stop a vehicle of mass 1000 kg running on a road with coefficient of friction between the tyres and the road is 0.4​

Answer 1

Answer:

Since frictional force is the only opposing force, it would be solely responsible for slowing down the car.

It is given that the coefficient of friction is 0.4, mass of the car is 1000 Kg.

We know that, frictional force is given by the formula:

⇒ f = μmg

where, μ is the coefficient of static friction, m is the mass of the object and g is the acceleration due to gravity.

Substituting the given values, we get:

⇒ f = 0.4 × 1000 Kg × 9.8 m/s²

⇒ f = 400 kg × 9.8 m/s²

⇒ f = 3920 N

Now if we had taken g to be 10 m/s², then the answer would be:

⇒ f = 0.4 × 1000 kg × 10 m/s²

⇒ f = 400 kg × 10 m/s²

⇒ f = 4000 N

These are the required answers.

Answer 2

Given :

• A vehicle of mass 1000 kg running on a road with coefficient of friction between the types and the road is 0.4 .

　

To find :

• How much force is required to stop the vehicle.

　

Using formula :

★ F = μmg.

　　　

Know terms :

1. (F) Force = To find?
2. (μ) Coefficient of friction = 0.4 .
3. (m) Mass = 1000 kg.
4. (g) Gravity = 9.8 m/s².

　

Calculations :

→ F = 0.4 × 1000 × 9.8

→ F = 400 × 9.8

→ F = 3920 Newton

　

Therefore, 3920 Newton is the force required to stop a vehicle.