Question

how much force is required to stop a vehicle of mass 1000kg running on a road with coefficient of friction between tyre and road is 0.4
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Answer 1

Answer:

Force due to friction is mgu where m is the mass, g is gravity, and I is the coefficient of friction. That gives you 1000*9.8*0.4 which equals 3920.

Answer 2

Explanation:

Force due to friction is mgu where m is the mass, g is gravity, and I is the coefficient of friction. hence ,1000×9.8×0.4=3920

force = 3920N

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