Question

how much force will be expireinced by a baller when a ball of 200 gm moving with a speed 20 m/s is caught in 5 sec​

Answer 1

Answer:

-0.8 Newtons

Explanation:

Given :

• Mass of the baller = m = 200 grams

• Initial velocity of the ball = u = 20 m/s

• Final velocity of the ball = v = 0 m/s (The ball will be stopped finally)

• Time taken = t = 5 seconds

To find :

• Force exerted to stop the ball

Force = m(v-u) / t

Force = 0.2(0-20)/5

Force = (0.2×-20)/5

Force = (-4)/5

Force = -0.8 Newtons

A force of -0.8 Newtons is exerted in the opposite direction of movement of ball

More :

Force = Mass×Acceleration

Answer 2

Given ,

• Mass of ball (m) = 200 gm or 0.2 kg
• Initial velocity (u) = 20 m/s
• Final velocity (v) = 0 m/s
• Time (t) = 5 sec

We know that ,

$\large \sf \fbox{Force = m \frac{(v - u)}{t} }$

Thus ,

$\sf \mapsto Force = 0.2 \times \frac{0 - 20}{5} \\ \\ \sf \mapsto Force = -0.2 \times 4 \\ \\ \sf \mapsto Force = -0.8 \: \: newton$

$\therefore \sf \underline{The \: force \: expireinced \: by \: a \: baller \: is \: 0.8 \: N}$