Question

how much gram K2r2O7 solid is required to prepare 0.05N of 100 cm3 the potassium dichromate solution​

Answer 1

Answer:

We will need 1.47 g of K₂Cr₂O₇.

Step-By-Step Explanation:

Given Data:-

Molarity = 0.05M

Volume = 100$cm^3$ = $\frac{100}{1000}$ = 0.1$dm^3$

Molar mass of K₂Cr₂O₇ = (39×2)+(52×2)+(16×7)

                                      = 78+104+112

                                      = 294 g/mole

To Find:-

Mass = ?

Formula:-

Mass = Molarity × Molar Mass ×Volume in $dm^3$

Solution:-

Mass = 0.05 × 294 ×0.1

         = 1.47 g

Result:-

We will need 1.47 g of K₂Cr₂O₇.