Question

how much grams of sodium chloride is present in 250mL of 0.50M NaCl solution

Answer 1

$\textbf{Your answer is --}$

Given, volume of solution is 250ml or 0.25 liter.

Molarity of NaCl = 0.50M

Now, according to molarity formula

M = n/V(in L)

where , n = no. of mole of solute(NaCl)

put the value

0.5 = n/0.25

=> n = 0.5×0.25

=> n = 0.125mole

So, number of mole of solute (NaCl) is 0.125mole present in solution .

Now , molecular mass of NaCl is

NaCl = 23+ 35.5 = 58.5

Now, according to formula

number if mole = mass of NaCl/molecular mass

=> 0.125 = mass of NaCl/58.5

=> mass of NaCl = 0.125×58.5 = 7.3125g


Hence, 7.3125 grams of sodium chloride is present in 250mL.


$\textbf{HOPE IT HELPS YOU }$

Answer 2

Hey !

Solution :

Given :

Molarity = 0.5 M NaCl solution

Volume = 0.25 Liters

To Calculate :

Mass of NaCl in solution. 

Proof :

Molarity = Number of moles / Volume of solution

=> Number of moles = Molarity * Volume of solution

=> Number of moles = 0.5 M * 0.25 L

=> Number of moles = 0.125 moles / liter

We also know that,

Number of moles = Given mass / Molecular mass

Molecular mass of NaCl = 23 + 35.5 = 58.5 g

Therefore, Substituting in the formula we get,

0.125 = Given mass / 58.5 g

=> Given mass = 0.125 * 58.5

=> Given mass = 7.3125 g

Hence the amount of NaCl in the solution is 7.3125 g.

Hope it helped :-)