Question

how much grams urea should be dissolved in 500g of water to get the boiling point of solution at 101.5°c​

Answer 1

Answer:

Explanation:

Boiling point of solution = 100.18^Given : Boiling point of solution =100.18  

o

C

K  

b

​

=0.512Kkgmol  

−1

 

K  

f

​

=1.86Kkgmol  

−1

 

ΔT Boiling =100.18  

o

−100  

o

=0.18

ΔT=K  

b

​

×molality

∴ molality =  

0.512

0.18

​

 

Now, ΔT  

freezing

​

=K  

f

​

×molality

                           =1.86×  

0.512

0.18

​

=0.6oC Kb = 0.512 K kg mol^-1