How much h2 in grams will be liberated if 1f electricity is passed through acidified water
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Answered by
72
Hey dear,
◆ Answer- 1 g H2
◆ Solution-
In acidified water, hydrogen is iberated at cathode by reaction-
2H+ + 2e- ---> H2
Two moles of e- are required to liberate 1 mole of H2.
Here, 1 F gives 1 mol of e- which will liberate 1/2 mol of H2.
Weight of H2 = Molecular mass × no of moles
Weight of H2 = 2 × 1/2
Weight of H2 = 1 g.
Hope this helps yoy...
Answered by
7
1 g hydrogen.
ANSWER IS CORRECT
ANSWER IS CORRECT
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