Question

how much h2o is obtained in combustion of 92 gm c2h5oh​

Answer 1

Answer:

The mass of water obtained during the combustion of $92$ g of ethanol is $108g$ of water·

Explanation:

Given that,

The mass of ethanol combusted $=$ $92$ g

The balanced chemical equation for the combustion of ethanol follows,

    $C_2H_5OH\ +\ 3\ O_2\ --->\ 2\ CO_2\ +\ 3\ H_2O$

From the equation, it is clear that

One mole of ethanol reacted with three moles of oxygen forms two moles of carbon dioxide and three moles of water·

⇒ Mass of $1$ mol of ethanol $=$ $46$ g

⇒ Mass of $1$ mol of water $=$ $18$ g

∴   Mass of $3$ mol of water $=$ $3g\ *\ 18g\ =\ 54g$

Therefore,

$46$ g of ethanol forms $54g$ of water during the combustion reaction·

$92$ g of ethanol forms $\frac{92g\ *\ 54g}{46g}$ of water·

That is,

 ⇒  $108g$ of water

Hence,

The mass of water obtained during the combustion of $92$ g of ethanol is $108g$ of water·