Question

how much h2so4 of density 1.84 gm/ml (98% pure by weight) should be taken to make 1 l normal solution

Answer 1

Explanation:

98% by weight of solution means 98g of H

2

SO

4

is present in 100g of solution.

Volume of solution =

density of solution

mass of solution

=

(1.8×1000)g/L

100g

Volume of solution =

18

1

L

Per cent H

2

SO

4

w/v of solution = molarity =

volume of solution (in L)

number of moles of H

2

SO

4

Molarity =

volume of solution

given mass of H

2

SO

4

/ molar mass of H

2

SO

4

Molarity =

1/18

98/98

=18M